937. Reorder Log Files
You have an array of logs. Each log is a space delimited string of words.
For each log, the first word in each log is an alphanumeric identifier. Then, either:
Each word after the identifier will consist only of lowercase letters, or;
Each word after the identifier will consist only of digits.
We will call these two varieties of logs letter-logs and digit-logs. It is guaranteed that each log has at least one word after its identifier.
Reorder the logs so that all of the letter-logs come before any digit-log. The letter-logs are ordered lexicographically ignoring identifier, with the identifier used in case of ties. The digit-logs should be put in their original order.
Return the final order of the logs.
Example 1:
Input: ["a1 9 2 3 1","g1 act car","zo4 4 7","ab1 off key dog","a8 act zoo"]
Output: ["g1 act car","a8 act zoo","ab1 off key dog","a1 9 2 3 1","zo4 4 7"]Note:
0 <= logs.length <= 1003 <= logs[i].length <= 100logs[i]is guaranteed to have an identifier, and a word after the identifier.
vector<string> reorderLogFiles(vector<string>& logs) {
vector<string> digit_container, res;
map<string, set<string> > mp; // without identifier -> with identifier
for (string& log : logs) {
int pos = log.find(' ');
string str = log.substr(pos + 1);
if (str[0] >= '0' && str[0] <= '9') {
digit_container.push_back(log);
} else {
mp[str].insert(log);
}
}
for (auto mit = mp.begin(); mit != mp.end(); ++mit) {
for (auto sit = mit->second.begin(); sit != mit->second.end(); ++sit) {
res.push_back(*sit);
}
}
for (const string& digit_str : digit_container) {
res.push_back(digit_str);
}
return res;
}Last updated
Was this helpful?