154. Find Minimum in Rotated Sorted Array II
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.
(i.e., [0,1,2,4,5,6,7]
might become [4,5,6,7,0,1,2]
).
Find the minimum element.
The array may contain duplicates.
Example 1:
Input: [1,3,5]
Output: 1
Example 2:
Input: [2,2,2,0,1]
Output: 0
Note:
This is a follow up problem to Find Minimum in Rotated Sorted Array.
Would allow duplicates affect the run-time complexity? How and why?
// Binary Search
int findMin(vector<int>& nums) { // time: O(logn); space: O(1)
if (nums.empty()) return -1;
int left = 0, right = nums.size() - 1;
while (left < right) {
if (nums[left] < nums[right]) { // no rotation in [left, right]
break;
}
int mid = left + (right - left) / 2;
if (nums[left] < nums[mid]) { // [left, mid] is sorted
left = mid + 1;
} else if (nums[left] > nums[mid]) { // [mid + 1, right] is sorted
right = mid;
} else {
++left;
}
}
return nums[left];
}
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