745. Prefix and Suffix Search

Given many words, words[i] has weight i.

Design a class WordFilter that supports one function, WordFilter.f(String prefix, String suffix). It will return the word with given prefix and suffix with maximum weight. If no word exists, return -1.

Examples:

Input:
WordFilter(["apple"])
WordFilter.f("a", "e") // returns 0
WordFilter.f("b", "") // returns -1

Note:

  1. words has length in range [1, 15000].

  2. For each test case, up to words.length queries WordFilter.f may be made.

  3. words[i] has length in range [1, 10].

  4. prefix, suffix have lengths in range [0, 10].

  5. words[i] and prefix, suffix queries consist of lowercase letters only.

class WordFilter {
public:
    WordFilter(vector<string>& words) { // time: O(N * L^2); space: O(N * L^2)
        for (int k = 0; k < words.size(); ++k) {
            for (int i = 0; i <= words[k].length(); ++i) {
                for (int j = 0; j <= words[k].length(); ++j) {
                    m[words[k].substr(0, i) + "#" + words[k].substr(words[k].length() - j)] = k;
                }
            }
        }
    }
    
    int f(string prefix, string suffix) { // time: O(1)
        string key_str = prefix + "#" + suffix;
        return m.count(key_str) != 0 ? m[key_str] : -1;
    }
private:
    unordered_map<string, int> m;
};

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