Given a linked list, swap every two adjacent nodes and return its head.
Given 1->2->3->4, you should return the list as 2->1->4->3.
// Iteration
ListNode* swapPairs(ListNode* head) { // time: O(n); space: O(1)
ListNode *dummy = new ListNode(-1);
dummy->next = head;
ListNode *pre = dummy, *cur = head, *nex = nullptr;
while (cur && cur->next) {
nex = cur->next;
cur->next = nex->next;
nex->next = cur;
pre->next = nex;
pre = cur;
cur = cur->next;
}
ListNode *res = dummy->next;
delete dummy;
return res;
}
// Iteration
ListNode* swapPairs(ListNode* head) { // time: O(n); space: O(1)
ListNode* dummy = new ListNode(-1);
ListNode *pre = dummy;
pre->next = head;
while (pre->next && pre->next->next) {
ListNode *t = pre->next->next;
pre->next->next = t->next;
t->next = pre->next;
pre->next = t;
pre = t->next;
}
ListNode* res = dummy->next;
delete dummy;
return res;
}
// Recursion
ListNode* swapPairs(ListNode* head) { // time: O(n); space: O(n)
if (!head || !head->next) return head;
ListNode *n = head->next;
head->next = swapPairs(n->next);
n->next = head;
return n;
}