Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
// Binary Search
int searchInsert(vector<int>& nums, int target) { // time: O(logn); space: O(1)
int left = 0, right = nums.size();
while (left < right) {
int mid = left + (right - left) / 2;
if (nums[mid] < target) {
left = mid + 1;
} else right = mid;
}
return left;
}